How to practice concept:compressibility-factor

Attempt a question, record the concept and assumptions, then check the available answer. Rework mistakes after revising the relevant concepts. Topic tags can overlap; review the question context.

Questions 1–5 of 5. Imported answers require independent review unless marked reviewed.

Topic practice 5 questionsPage 1 of 1

Question 15

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For the Refrigerant R-134 (at 1 MPa and 50°C), the difference between the specific volume computed by assuming it to be an ideal gas and its actual specific volume is:

. If the compressibility factor associated with this state is

, then

__________

m³/kg (3 decimal places).
Here

is the specific volume calculated using the compressibility factor.
For Refrigerant R-134 (at 1 MPa and 50°C): The characteristic gas constant: 0.0815 kJ/(kgK), The critical pressure and temperature are, respectively,

MPa and

K.

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Question 7

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Let

represents the compressibility factor of air at 2 bar and 600 K,

represents the compressibility factor of air at 1 bar and 300 K. If air is assumed to be an ideal gas having gas constant of 0.287 kJ/kg.K, then

is ________.

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Question 10

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A gas obeys the van der Waals equation of state

, where

and

are van der Waals constants. The compressibility factor

in the limit of high specific volume (

) is
Your answerChoose one option.

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Question 5

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The value of the compressibility factor at the critical point evaluated using the van der Waals equation of state is
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Question 15

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Methane has compressibility factor value of 0.9 at reduced pressure of 1.0 and reduced temperature of 1.5. For propane, the critical temperature and pressure are 369.8 K and 42.48 bar, respectively. Take R = 8.314 kJ/kmol.K. Applying the principle of corresponding states, the molar volume of propane (in m

/kmol) at the same reduced pressure and temperature is
Your answerChoose one option.

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