Life Sciences
GATE XL concept:rate-constant PYQs
Build your understanding with focused practice from past exam papers.
How to practice concept:rate-constant
Attempt a question, record the concept and assumptions, then check the available answer. Rework mistakes after revising the relevant concepts. Topic tags can overlap; review the question context.
Questions 1–6 of 6. Imported answers require independent review unless marked reviewed.
Question 21
Open questionXL-PMCQ2 marksNeeds review
For product formation from only one type of reactant (e.g. A → product), the CORRECT match for the order of the reaction (given in Column I) with the half-life expression (given in Column II) is
([A]₀ is the initial concentration and kᵣ is the rate constant)
Column I: Order | Column II: Half-life expression |
|---|---|
i. Zero | P. ln 2 / kᵣ |
ii. First | Q. [A]₀ / 2kᵣ |
iii. Second | R. 1 / kᵣ[A]₀ |
| S. 2kᵣ / [A]₀ |
Your answerChoose one option.
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Open questionXL-PMCQ1 markNeeds review
Consider a second order reaction,
The concentration of A is represented as [A].
Which of the following is the CORRECT plot for determining the rate constant for the above reaction?
Your answerChoose one option.
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You can attempt this question now. Sign in to view the answer key, explanations and discussion.Log in to check answerQuestion 12
Open questionXL-PNAT2 marksNeeds review
A molecule in solution crystallizes into two different crystal forms with rate constants of 0.02 s
and 0.13 s
. If the crystallization is assumed to be under kinetic control, then the half-life (in seconds, rounded off to one decimal place) of the molecule is _________.Log in to check the answer
You can attempt this question now. Sign in to view the answer key, explanations and discussion.Log in to check answerQuestion 14
Open questionXL-PNAT2 marksNeeds review
The activation energy (
) estimated for a reaction from the Arrhenius equation is 21 kJ mol
. If the frequency factor is assumed to be independent of temperature, then the ratio of the rate constants determined at 298 K and 260 K is ________ (rounded off to two decimal places). (Given: Gas constant, R = 8.315 J K
mol
)Log in to check the answer
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Open questionXL-PMCQ2 marksNeeds review
For the reaction mechanism,
;
. For this step, assume
.
: rate constant for this step. The rate law isYour answerChoose one option.
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You can attempt this question now. Sign in to view the answer key, explanations and discussion.Log in to check answerQuestion 14
Open questionXL-PNAT2 marksNeeds review
The activation energy (Eₐ) values for two reactions carried out at 25 °C differ by 5.0 kJ mol⁻¹. If the pre-exponential factors (A₁ and A₂) for these two reactions are of the same magnitude, the ratio of rate constants (k₁/k₂) is ______ (up to two decimal places).
(Given: Gas constant R = 8.314 J K⁻¹ mol⁻¹)
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