Life Sciences
GATE XL topic:biochemistry-molecular-biology PYQs
Build your understanding with focused practice from past exam papers.
Questions 21–30 of 33. Imported answers require independent review unless marked reviewed.
Question 19
Open questionXL-TNAT2 marksNeeds review
An enzyme catalyzes the conversion of 30 μM of a substrate to product at reaction velocity of 9.0 μM s⁻¹. When [Eₜ] = 30 nM and Kₘ = 10 μM, Kcat / Kₘ of enzyme will be n × 10⁷ M⁻¹ s⁻¹. The value of n is ________ (in integer).
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Open questionXL-TMCQ2 marksNeeds review
Match the proteins in Column I with the organs in which they are maximally expressed in Column II.
Column I | Column II |
|---|---|
P. Keratin | (i) Liver |
Q. Surfactants | (ii) Pancreas |
R. Pro-carboxypeptidase | (iii) Lung |
S. Albumin | (iv) Skin |
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You can attempt this question now. Sign in to view the answer key, explanations and discussion.Log in to check answerQuestion 8
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Consider the given peptide, Ala-Glu-Val-Asn-Ile-Asp-Pro-Asp-Gln-Gly-Asp. The net charge on the peptide at pH 1.0 will be_____
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In a 150 base pair double stranded B-DNA, 70% of purines are adenine bases. The total number of hydrogen bonds (Watson–Crick base pairing) in the DNA will be _____.
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Open questionXL-TMCQ2 marksNeeds review
Match the given vitamins in Column I with the related proteins in Column II
Column I
a) Vitamin C
b) Vitamin K
c) Vitamin A
d) Vitamin B₁
Column II
Thrombin
Rhodopsin
Pyruvate dehydrogenase
Prolyl hydroxylase
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You can attempt this question now. Sign in to view the answer key, explanations and discussion.Log in to check answerQuestion 17
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The molecular weight of a double stranded DNA fragment present in mitochondria is 7.92 × 10⁸ g mol⁻¹. A pair of nucleotide contributes 0.34 nm to the length of DNA and the average molecular weight of a nucleotide is 330 g mol⁻¹. The number of protein molecules, consisting of 200 amino acids each, coded by this mitochondrial DNA is _____.
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You can attempt this question now. Sign in to view the answer key, explanations and discussion.Log in to check answerQuestion 18
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An enzyme that follows Michaelis-Menten kinetics catalyses the conversion of 35 μM substrate into product with a reaction velocity of 10 μM s⁻¹. The Kₘ and kₐₜ for the substrate are 14 μM and 500 s⁻¹ respectively. The total amount of enzyme taken for the enzyme reaction is ____ nM.
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You can attempt this question now. Sign in to view the answer key, explanations and discussion.Log in to check answerQuestion 3
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In a chemical reaction where the substrate and product are in equilibrium in solution, what will occur if an enzyme is added?
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Open questionXL-TMCQ2 marksNeeds review
Glucose monomers are joined together by glycosidic linkages to form a cellulose polymer. During this process, changes in the free energy, total energy, and entropy respectively are represented correctly by which ONE of the following options?
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The enzyme amylase can break alpha glycosidic linkages between glucose monomers. Hence, amylase can digest which one of the following carbohydrates?
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