GATE XL topic:biology PYQs & Answers — Page 47

Questions 461–470 of 1235. Imported answers require independent review unless marked reviewed.

Match the syndromes listed in Column I with the cause/symptoms listed in Column II

Column I: P. Prader-Willi syndrome; Q. Down syndrome; R. Cushing syndrome; S. Turner syndrome; T. Fanconi syndrome

Column II: (i) a collection of signs and symptoms due to prolonged exposure to corticosteroids like cortisol; (ii) a syndrome of inadequate reabsorption in the proximal renal tubule of the kidney; (iii) a genetic disorder usually caused by the deletion of a part of chromosome 15; (iv) a genetic disorder caused by the presence of all or part of a third copy of chromosome 21; (v) a genetic condition in which a female has partially or completely missing an X chromosome

Your answerChoose one option.

P – (ii) ; Q – (v) ; R – (iv) ; S – (iii) ; T – (i)

P – (iv) ; Q – (ii) ; R – (i) ; S – (iii) ; T – (v)

P – (iii) ; Q – (iv) ; R – (i) ; S – (v) ; T – (ii)

P – (v) ; Q – (iv) ; R – (ii) ; S – (i) ; T – (iii)

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Match the immunological statements in Column I with the appropriate descriptions from Column II

Column I: P. Active acquired immunity; Q. First line of defense; R. Passive natural immunity; S. Second line of defense

Column II: (i) Complement proteins and interferons; (ii) Direct contact with pathogens that enter the body; (iii) Surface barriers; (iv) Antibodies pass through placenta

Your answerChoose one option.

P – (ii) ; Q – (iii) ; R – (iv) ; S – (i)

P – (iv) ; Q – (iii) ; R – (i) ; S – (ii)

P – (iv) ; Q – (ii) ; R – (iii) ; S – (i)

P – (i) ; Q – (iv) ; R – (iii) ; S – (ii)

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Match the standard/stated cofactors in Column I with their respective enzymes in Column II

Column I P. Cu²⁺ Q. Se R. Ni²⁺ S. K⁺ T. Mo

Column II (i) Dinitrogenase (ii) Cytochrome oxidase (iii) Pyruvate kinase (iv) Glutathione peroxidase (v) Urease

Your answerChoose one option.

P – (v) ; Q – (ii) ; R – (iv) ; S – (i) ; T – (iii)

P – (ii) ; Q – (iv) ; R – (v) ; S – (iii) ; T – (i)

P – (iv) ; Q – (ii) ; R – (iii) ; S – (i) ; T – (v)

P – (ii) ; Q – (i) ; R – (iii) ; S – (iv) ; T – (v)

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The presence of excess glucose has been known to prevent the induction of lac operon as well as other operon controlling enzymes involved in carbohydrate metabolism in E. coli. Which of the following processes define(s) the phenomenon?

Your answerSelect all correct options. You can choose more than one.

Catabolite repression

Attenuation

Glucose effect

Feedback inhibition

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Which of the following techniques is/are used for determining the three-dimensional structure of proteins?

Your answerSelect all correct options. You can choose more than one.

Cryo-electron Microscopy

Circular Dichroism

Nuclear Magnetic Resonance Spectroscopy

X-ray Diffraction

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Among the following statements, which is/are TRUE regarding the replication of DNA?

Your answerSelect all correct options. You can choose more than one.

Replication is bidirectional and conservative in nature.

Replication in eukaryotes takes place at multiple Ori sites simultaneously.

Both the strands replicate in discontinuous manner.

One strand replicates in continuous while the other replicates in discontinuous manner.

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Which of the following statements is/are TRUE for Colchicine?

Your answerSelect all correct options. You can choose more than one.

It binds to tubulin molecule and disrupts the assembly/polymerization of microtubule.

It inhibits crossover of chromosomes during meiosis.

It inhibits chromosome condensation during Prophase.

It blocks mitotic cells in Metaphase.

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Wild-type Drosophila females having three linked genes (A,B,C) were crossed with triple recessive mutant (aabbcc) males. The F₁ female progenies (AaBbCc) were back crossed with the triple negative mutant (aabbcc) males. The cross resulted in following number of progenies in F₂:

AaBbCc 241

Aabbcc 112

aaBbCc 103

aabbcc 252

aaBbcc 17

aabBCc 134

AabbCc 14

AaBbcc 127

1000

The order of genes as determined from the above data was found to be “ABC” (note that the order is equivalent to “CBA” and the order outside the markers are arbitrary).

The recombination map distance (in centi Morgan) between “A to C” is ______ (round off to one decimal place).

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The length of a double helical DNA molecule is 13.6 km. If the DNA double helix weighs 1 × 10⁻¹⁸ g per 1000 nucleotide pairs and rise per base pair is 3.4 Å, then weight of the double helical DNA molecule (in nanogram) will be ______ (in integer).

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Choose the correct group of fat soluble vitamins

Your answerChoose one option.

Cholecalciferol, α-Tocopherol, Menadione

Thiamine, Cholecalciferol, α-Tocopherol

Niacin, α-Tocopherol, Menadione

Biotin, Thiamin, Niacin

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GATE XL topic:biology PYQs

Question 95

Question 96

Question 97

Question 98

Question 99

Question 100

Question 101

Question 102

Question 103

Question 104