Life Sciences
GATE XL topic:life-sciences PYQs
Build your understanding with focused practice from past exam papers.
Questions 541–550 of 1235. Imported answers require independent review unless marked reviewed.
Question 53
Open questionXL-RMSQ1 markNeeds review
Which of the following is/are part of marine ecosystem?
Your answerSelect all correct options. You can choose more than one.
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Open questionXL-RNAT1 markNeeds review
In NADP⁺-malic enzyme type C₄ photosynthesis cycle,
molecule(s) of ATP is/are required for the assimilation of one molecule of CO₂. The value of
is ______ (in integer).Log in to check the answer
You can attempt this question now. Sign in to view the answer key, explanations and discussion.Log in to check answerQuestion 55
Open questionXL-RMCQ2 marksNeeds review
An Arabidopsis thaliana mutant plant developed defective flowers with altered floral organ identity and patterning. In this mutant, the four floral whorls contain Sepal-Sepal-Carpel-Carpel, from the periphery to the center of the flower.
Based on the typical ABC model of floral organ patterning, which among the following are mutated in this plant?
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Open questionXL-RMCQ2 marksNeeds review
Match the secondary metabolites in Group-I with types of secondary metabolites in Group-II in CORRECT order.
Group-I:
P. Myrcene
Q. β-Farnesene
R. Amygdalin
S. Nicotine
T. Luteolin
Group-II:
I. Sesquiterpene
II. Cyanogenic glycoside
III. Flavone
IV. Alkaloid
V. Monoterpene
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You can attempt this question now. Sign in to view the answer key, explanations and discussion.Log in to check answerQuestion 57
Open questionXL-RMCQ2 marksNeeds review
Match Group-I (enzyme), Group-II (reaction catalyzed by the enzyme), and Group-III (subcellular location of the enzyme and the associated metabolic process) in CORRECT combination.
Group-I:
P. PEP carboxylase
Q. Rubisco
R. Glycolate oxidase
S. Pyruvate dehydrogenase
Group-II:
I. 2 Glycolate + 2 O₂ = 2 Glyoxylate + 2 H₂O₂
II. Pyruvate + NAD⁺ + CoA = Acetyl-CoA + CO₂ + NADH
III. Phosphoenolpyruvate + HCO₃⁻ = Oxaloacetate + Pi
IV. 3 (Ribulose 1,5-bisphosphate) + 3 CO₂ + 3 H₂O = 6 (3-phosphoglycerate) + 6 H⁺
Group-III:
a. Cytosol – C₄ cycle
b. Peroxisome – C₂ cycle
c. Mitochondria – aerobic respiration
d. Chloroplast – C₃ cycle
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You can attempt this question now. Sign in to view the answer key, explanations and discussion.Log in to check answerQuestion 58
Open questionXL-RMCQ2 marksNeeds review
Match Group-I (selection agent) and Group-II (gene) in CORRECT combination.
Group-I: P. Kanamycin; Q. Hygromycin; R. Phosphinothricin; S. Mannose.
Group-II: I. pmi; II. bar; III. nptII; IV. ptxD; V. dhfr; VI. hpt
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Open questionXL-RMCQ2 marksNeeds review
Match Group I (plant natural product), Group II (class) and Group III (source plant) in CORRECT combination.
Group-I: P. Reserpine; Q. Resveratrol; R. Picrocrocin; S. Linamarin.
Group-II: I. Stilbenes; II. Cyanogenic glycoside; III. Alkaloid; IV. Monoterpene glycoside.
Group-III: a. Manihot esculenta; b. Crocus sativus; c. Vitis vinifera; d. Rauvolfia serpentina
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Open questionXL-RMCQ2 marksNeeds review
Match Group I (plant disease), Group II (causal organism) and Group III (affected plant) in CORRECT combination.
Group-I: P. Karnal Bunt; Q. Ergot; R. Late blight; S. Powdery mildew.
Group-II: I. Phytophthora infestans; II. Blumeria graminis; III. Neovossia indica; IV. Puccinia recondita; V. Claviceps purpurea; VI. Alternaria solani.
Group-III: a. Rice; b. Potato; c. Rye; d. Wheat; e. Barley; f. Brinjal
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Open questionXL-RMCQ2 marksNeeds review
Make CORRECT match between Group-I and Group-II, in relation to interaction between two species.
Group-I: P. Neutralism; Q. Allelopathy; R. Amensalism; S. Mutualism.
Group-II: I. neither can survive under natural condition without the other; II. direct inhibition of one species by the other species using toxic compound; III. neither is affected by the association with the other; IV. one is inhibited and the other is not affected.
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Open questionXL-RMSQ2 marksNeeds review
Which of the following matches is/are CORRECT?
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