Life Sciences
GATE XL year:2019 PYQs
Build your understanding with focused practice from past exam papers.
Questions 101–110 of 125. Imported answers require independent review unless marked reviewed.
Question 16
Open questionXL-TMCQ2 marksNeeds review
Match the hormones in Column I to their respective physiological effects in Column II
Column I
a) Melatonin
b) Oxytocin
c) Cholecystokinin
d) Prolactin
e) Somatostatin
Column II
Inhibition of secretion of growth hormone
Synthesis of milk in mammary gland
Secretion of milk and uterine contraction
Secretion of enzymes from pancreatic acinar cells
Regulation of circadian rhythms
Your answerChoose one option.
Log in to check the answer
You can attempt this question now. Sign in to view the answer key, explanations and discussion.Log in to check answerQuestion 17
Open questionXL-TNAT2 marksNeeds review
The molecular weight of a double stranded DNA fragment present in mitochondria is 7.92 × 10⁸ g mol⁻¹. A pair of nucleotide contributes 0.34 nm to the length of DNA and the average molecular weight of a nucleotide is 330 g mol⁻¹. The number of protein molecules, consisting of 200 amino acids each, coded by this mitochondrial DNA is _____.
Log in to check the answer
You can attempt this question now. Sign in to view the answer key, explanations and discussion.Log in to check answerQuestion 18
Open questionXL-TNAT2 marksNeeds review
An enzyme that follows Michaelis-Menten kinetics catalyses the conversion of 35 μM substrate into product with a reaction velocity of 10 μM s⁻¹. The Kₘ and kₐₜ for the substrate are 14 μM and 500 s⁻¹ respectively. The total amount of enzyme taken for the enzyme reaction is ____ nM.
Log in to check the answer
You can attempt this question now. Sign in to view the answer key, explanations and discussion.Log in to check answerQuestion 19
Open questionXL-TNAT2 marksNeeds review
A distinctly large population of randomly mating laboratory mice contains 36% albino mice, which is caused by a double recessive genotype (aa). The black coloured mice in the population is due to dominant genotype (AA/Aa). Considering the fact that this population is in Hardy-Weinberg equilibrium, the frequency of heterozygous alleles (Aa) in this population is _____ (round off to 2 decimal places).
Log in to check the answer
You can attempt this question now. Sign in to view the answer key, explanations and discussion.Log in to check answerQuestion 20
Open questionXL-TNAT2 marksNeeds review
A genetic cross was made between homozygous wild-type males (a⁺b⁺c⁺) and triple-mutant females (abc) of Drosophila melanogaster. Then the F₁ males (a⁺b⁺c⁺) were back crossed to the triple-mutant females which resulted in the following F₂ progenies:
Progeny | Number |
|---|---|
a⁺bc | 16 |
ab⁺c | 115 |
abc | 311 |
a⁺b⁺c | 64 |
ab⁺c⁺ | 61 |
a⁺b⁺c⁺ | 317 |
a⁺bc⁺ | 99 |
ab c⁺ | 17 |
Total | 1000 |
The order of genes as determined from the above data was found to be “b a c” (note that the order is equivalent to “c a b” and the order of outside markers are arbitrary).
The map distance between “b and c” is _____ centiMorgan (round off to 1 decimal place).
Log in to check the answer
You can attempt this question now. Sign in to view the answer key, explanations and discussion.Log in to check answerQuestion 1
Open questionXL-UMCQ1 markNeeds review
Colloidal stability of milk casein is because of the highly hydrated carbohydrate residues in __________.
Your answerChoose one option.
Log in to check the answer
You can attempt this question now. Sign in to view the answer key, explanations and discussion.Log in to check answerQuestion 2
Open questionXL-UMCQ1 markNeeds review
Rice bran is stabilized prior to oil extraction to protect it from the activity of __________.
Your answerChoose one option.
Log in to check the answer
You can attempt this question now. Sign in to view the answer key, explanations and discussion.Log in to check answerQuestion 3
Open questionXL-UMCQ1 markNeeds review
Sticking of powder to wall of the chamber during spray drying of fruit juice is due to _____.
Your answerChoose one option.
Log in to check the answer
You can attempt this question now. Sign in to view the answer key, explanations and discussion.Log in to check answerQuestion 4
Open questionXL-UMCQ1 markNeeds review
Thearubins and theaflavins in black tea are formed by the oxidation and dimerization of __________.
Your answerChoose one option.
Log in to check the answer
You can attempt this question now. Sign in to view the answer key, explanations and discussion.Log in to check answerQuestion 5
Open questionXL-UMCQ1 markNeeds review
Ratio of Schmidt number to Lewis number is __________.
Your answerChoose one option.
Log in to check the answer
You can attempt this question now. Sign in to view the answer key, explanations and discussion.Log in to check answer