Mechanical Engineering
2020 · Paper 2
Take it one question at a time. Try an answer, then check your understanding.
Complete GATE ME 2020 Paper 2 overview, original pages and practice · Timed previous-paper practice
Questions 52–54 of 65. Imported answers require review unless explicitly marked reviewed.
Question 42
Open questionMENAT2 marksNeeds review
A mould cavity of 120 cm
volume has to be filled through a sprue of 10 cm length feeding a horizontal runner. Cross-sectional area at the base of the sprue is 2 cm
. Consider acceleration due to gravity as 9.81 m/s
. Neglecting frictional losses due to molten metal flow, the time taken to fill the mould cavity is ______ seconds (round off to 2 decimal places).Log in to check the answer
You can attempt this question now. Sign in to view the answer key, explanations and discussion.Log in to check answerQuestion 43
Open questionMENAT2 marksNeeds review
A cylindrical bar with 200 mm diameter is being turned with a tool having geometry 0° - 9° - 7° - 8° - 15° - 30° - 0.05 inch (Coordinate system, ASA) resulting in a cutting force
. If the tool geometry is changed to 0° - 9° - 7° - 8° - 15° - 0° - 0.05 inch (Coordinate system, ASA) and all other parameters remain unchanged, the cutting force changes to
. Specific cutting energy (in J/mm
) is
, where
is the specific energy coefficient, and
is the uncut thickness in mm. The value of percentage change in cutting force
, i.e.
, is ______ (round off to one decimal place).Log in to check the answer
You can attempt this question now. Sign in to view the answer key, explanations and discussion.Log in to check answerQuestion 44
Open questionMENAT2 marksNeeds review
There are two identical shape machines S
and S
. In machine S
, the width of the workpiece is increased by 10% and the feed is decreased by 10%, with respect to that of S
. If all other conditions remain the same then the ratio of total time per pass in S
and S
will be ______ (round off to one decimal place).Log in to check the answer
You can attempt this question now. Sign in to view the answer key, explanations and discussion.Log in to check answer