Questions 171–180 of 201. Imported answers require independent review unless marked reviewed.

Topic practice 201 questionsPage 18 of 21

Question 45

Open question
BTNAT2 marksNeeds review
An aqueous solution containing 6.8 mg/L of an antibiotic is extracted with amyl acetate. If the partition coefficient of the antibiotic is 70 and the ratio of water to solvent is 85, then the extraction factor is


Log in to check the answer

You can attempt this question now. Sign in to view the answer key, explanations and discussion.Log in to check answer

Question 46

Open question
BTNAT2 marksNeeds review
A microbial strain is cultured in a 100 L stirred fermenter for secondary metabolite production. If the specific rate of oxygen uptake is 0.4 h⁻¹ and the oxygen solubility in the broth is 8 mg/L, then the volumetric mass transfer coefficient (

) (in s⁻¹) of oxygen required to achieve a maximum cell concentration of 12 g/L is (up to two decimal places)


Log in to check the answer

You can attempt this question now. Sign in to view the answer key, explanations and discussion.Log in to check answer

Question 47

Open question
BTNAT2 marksNeeds review
In a chemostat, the feed flow rate and culture volume are 100 ml/h and 1.0 L, respectively. With glucose as substrate, the values of

and

are 0.2 h⁻¹ and 1 g/L, respectively. For a glucose concentration of 10 g/L in the feed, the effluent substrate concentration (in g/L) is


Log in to check the answer

You can attempt this question now. Sign in to view the answer key, explanations and discussion.Log in to check answer

Question 48

Open question
BTNAT2 marksNeeds review
Mammalian cells in active growth phase were seeded at a density of 1×10⁵ cells/ml. After 72 hours, 1×10⁶ cells/ml were obtained. The population doubling time of the cells in hours is (up to two decimal places)


Log in to check the answer

You can attempt this question now. Sign in to view the answer key, explanations and discussion.Log in to check answer

Question 49

Open question
BTNAT2 marksNeeds review
Yeast converts glucose to ethanol and carbon dioxide by glycolysis as per the following reaction:

Assuming complete conversion, the amount of ethanol produced (in g) from 200 g of glucose is (up to two decimal places)


Log in to check the answer

You can attempt this question now. Sign in to view the answer key, explanations and discussion.Log in to check answer

Question 50

Open question
BTNAT2 marksNeeds review
At the end of a batch culture, glucose solution is added at a flow rate of 200 ml/h. If the culture volume after 2 h of glucose addition is 1000 ml, the initial culture volume (in ml) is


Log in to check the answer

You can attempt this question now. Sign in to view the answer key, explanations and discussion.Log in to check answer

Question 51

Open question
BTNAT2 marksNeeds review
Consider the following alignment of two DNA sequences:

Assuming an affine gap scoring scheme of an identity matrix for substitution, a gap initiation penalty of 1 and a gap extension penalty of 0.1, the score of the alignment is (up to one decimal place)


Log in to check the answer

You can attempt this question now. Sign in to view the answer key, explanations and discussion.Log in to check answer

Question 52

Open question
BTNAT2 marksNeeds review
First order deactivation rate constants for soluble and immobilized amyloglucosidase enzyme are 0.03 min⁻¹ and 0.005 min⁻¹, respectively. The ratio of half-life of the immobilized enzyme to that of the soluble enzyme is (rounded off to the nearest integer)


Log in to check the answer

You can attempt this question now. Sign in to view the answer key, explanations and discussion.Log in to check answer

Question 53

Open question
BTNAT2 marksNeeds review
Consider a simple uni-substrate enzyme that follows Michaelis-Menten kinetics. When the enzyme catalyzed reaction was carried out in the presence of 10 nM concentration of an inhibitor, there was no change in the maximal velocity. However, the slope of the Lineweaver-Burk plot increased 3-fold. The dissociation constant for the enzyme-inhibitor complex (in nM) is


Log in to check the answer

You can attempt this question now. Sign in to view the answer key, explanations and discussion.Log in to check answer

Question 54

Open question
BTNAT2 marksNeeds review
The product of complete digestion of the plasmid shown below with EcoRI and HaeII was purified and used as a template in a reaction containing Klenow fragment of DNA polymerase, dNTPs and [α-³²P]-dATP in a suitable reaction buffer. The product thus obtained was purified and subjected to gel electrophoresis followed by autoradiography.
Diagram for Biotechnology question 54

The number of bands that will appear on the X-ray film is


Log in to check the answer

You can attempt this question now. Sign in to view the answer key, explanations and discussion.Log in to check answer