GATE BT · 2018 · BT
Question 52: Bioreactor engineering
Give it a try, then reveal the answer to check your work.
Question 52
BTNAT2 marksNeeds review
First order deactivation rate constants for soluble and immobilized amyloglucosidase enzyme are 0.03 min⁻¹ and 0.005 min⁻¹, respectively. The ratio of half-life of the immobilized enzyme to that of the soluble enzyme is (rounded off to the nearest integer)
Log in to check the answer
You can attempt this question now. Sign in to view the answer key, explanations and discussion.Log in to check answerEXPLORE & PRACTISE
Paper and topic context
See where this question comes from and choose what to practise next.
2018BT
GATE BT 2018 · Paper 1
Biotechnology · Original paper archive
- Section
- Biotechnology
- Question type
- Numerical answer (NAT)
- Marks
- 2 marks
Practise related topics
Explore more previous year questions using this question’s imported topic tags.
biotechnology
GATE BT previous year questions
biology
GATE BT previous year questions
life sciences
GATE BT previous year questions
bioreactor engineering
GATE BT previous year questions
Comments
Ask a question, share your approach, or help someone understand.
Log in to view the discussion
You’re not logged in. Log in or create an account to see discussions and add comments.