Question 39

CHMCQ2 marksNeeds review
A volatile organic compound (VOC) is to be adsorbed from air onto a bed of activated carbon. The equilibrium capacity of activated carbon at the feed conditions is 0.4 grams VOC per gram of activated carbon. The column contains 4 grams of activated carbon per cm

of cross-section. The feed rate into the adsorber column is 0.2 grams VOC cm

h

. Breakthrough time is defined as the time at which the concentration at the exit of the bed (

) reaches a value of

, where

is the concentration of VOC in the feed. The breakthrough time for the bed is 2 h. The area under the

curve between the initial and breakthrough times is 0.1 h. Which one of the following is the fraction of unused bed at breakthrough?
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2026CH

GATE CH 2026 · Paper 1

Chemical Engineering · Original paper archive

Section
Chemical Engineering
Question type
Multiple choice (MCQ)
Marks
2 marks

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