Question 41

MTNAT2 marksNeeds review
Steady state radial heat conduction through a hollow, infinitely long zirconia cylinder is governed by the following ordinary differential equation:

Here, T is the temperature and r is the radial distance. The inner surface of the hollow cylinder is maintained at 1473 K and the outer surface at 973 K. The rate of heat loss per unit length through the outer surface of the hollow cylinder (in W.m⁻¹, rounded off to the nearest integer) is _____________.
Given: Inner radius of cylinder = 0.05 m; outer radius of cylinder = 0.07 m and thermal conductivity of zirconia (k) = 2 W.m⁻¹.K⁻¹.

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2019MT

GATE MT 2019 · Paper 1

Metallurgical Engineering · Original paper archive

Section
Metallurgical Engineering
Question type
Numerical answer (NAT)
Marks
2 marks

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